Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Ka | 4200 | 254 | 9 | 28.2222 |
Nā | 443 | 20 | 1 | 20.0000 |
Ahakoa | 188 | 15 | 1 | 15.0000 |
I | 2823 | 102 | 8 | 12.7500 |
hunga | 474 | 38 | 3 | 12.6667 |
Me | 678 | 48 | 4 | 12.0000 |
click | 116 | 12 | 1 | 12.0000 |
Kia | 517 | 44 | 4 | 11.0000 |
Kua | 810 | 65 | 6 | 10.8333 |
te | 59453 | 1892 | 178 | 10.6292 |
Tokerau | 152 | 10 | 1 | 10.0000 |
E | 2295 | 103 | 11 | 9.3636 |
Tēnā | 70 | 9 | 1 | 9.0000 |
Nō | 355 | 9 | 1 | 9.0000 |
Haere | 119 | 9 | 1 | 9.0000 |
He | 4159 | 164 | 20 | 8.2000 |
Zealand | 304 | 8 | 1 | 8.0000 |
Koia | 173 | 8 | 1 | 8.0000 |
Anei | 103 | 8 | 1 | 8.0000 |
No | 166 | 7 | 1 | 7.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
mai | 4465 | 25 | 207 | 0.1208 |
kōwhiringa | 394 | 1 | 8 | 0.1250 |
kamupene | 79 | 1 | 7 | 0.1429 |
kōwae | 95 | 1 | 6 | 0.1667 |
Ehara | 277 | 3 | 17 | 0.1765 |
noa | 1118 | 10 | 54 | 0.1852 |
nei | 2638 | 27 | 138 | 0.1957 |
pire | 25 | 1 | 5 | 0.2000 |
ana | 6699 | 47 | 235 | 0.2000 |
kaiwhakaako | 46 | 1 | 5 | 0.2000 |
whakatū | 72 | 1 | 5 | 0.2000 |
whakakī | 30 | 1 | 5 | 0.2000 |
waihanga | 152 | 1 | 5 | 0.2000 |
hopukina | 31 | 1 | 5 | 0.2000 |
ake | 2124 | 25 | 119 | 0.2101 |
atu | 4437 | 43 | 182 | 0.2363 |
ai | 3518 | 40 | 161 | 0.2484 |
me | 7123 | 66 | 264 | 0.2500 |
korua | 26 | 1 | 4 | 0.2500 |
Marautanga | 115 | 1 | 4 | 0.2500 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II